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100x-x^2=2475
We move all terms to the left:
100x-x^2-(2475)=0
We add all the numbers together, and all the variables
-1x^2+100x-2475=0
a = -1; b = 100; c = -2475;
Δ = b2-4ac
Δ = 1002-4·(-1)·(-2475)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-10}{2*-1}=\frac{-110}{-2} =+55 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+10}{2*-1}=\frac{-90}{-2} =+45 $
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